5x^2+80x-460=0

Solution for 5x^2+80x-460=0 equation:

5x^2+80x-460=0

a = 5; b = 80; c = -460;
Δ = b2-4ac
Δ = 802-4·5·(-460)
Δ = 15600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15600}=\sqrt{400*39}=\sqrt{400}*\sqrt{39}=20\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-20\sqrt{39}}{2*5}=\frac{-80-20\sqrt{39}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+20\sqrt{39}}{2*5}=\frac{-80+20\sqrt{39}}{10}
$